To find the value of f'(2), we first need to find the derivative of the function f(x) = 7.6x^2 + 5.3x + 2.7.

The derivative of a function is found using the power rule, which states that the derivative of x^n is n*x^(n-1).

Applying the power rule to each term in the function:

- The derivative of 7.6x^2 is 2*7.6x = 15.2x.
- The derivative of 5.3x is 5.3.
- The derivative of a constant, like 2.7, is 0.

So, the derivative of the function f(x), or f'(x), is 15.2x + 5.3.

To find the value of f'(2), we substitute x = 2 into the derivative:

f'(2) = 15.2*2 + 5.3 = 30.4 + 5.3 = 35.7.

Question

To find the value of f'(2), we first need to find the derivative of the function f(x) = 7.6x^2 + 5.3x + 2.7.

The derivative of a function is found using the power rule, which states that the derivative of x^n is n*x^(n-1).

Applying the power rule to each term in the function:

- The derivative of 7.6x^2 is 2*7.6x = 15.2x.
- The derivative of 5.3x is 5.3.
- The derivative of a constant, like 2.7, is 0.

So, the derivative of the function f(x), or f'(x), is 15.2x + 5.3.

To find the value of f'(2), we substitute x = 2 into the derivative:

f'(2) = 15.2*2 + 5.3 = 30.4 + 5.3 = 35.7.

Knowee AI · Accepted Answer

To find the value of f'(2), we first need to find the derivative of the function f(x) = 7.6x^2 + 5.3x + 2.7.

The derivative of a function is found using the power rule, which states that the derivative of x^n is n*x^(n-1).

Applying the power rule to each term in the function:

- The derivative of 7.6x^2 is 2*7.6x = 15.2x.
- The derivative of 5.3x is 5.3.
- The derivative of a constant, like 2.7, is 0.

So, the derivative of the function f(x), or f'(x), is 15.2x + 5.3.

To find the value of f'(2), we substitute x = 2 into the derivative:

f'(2) = 15.2*2 + 5.3 = 30.4 + 5.3 = 35.7.

Define a quadratic function f(x)=7.6x^2+5.3x+2.7 for all positive x. Denote f'(x) to be the derivative of f(x). What is the value of f'(2)?