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Define a function f(x)=2e^x-x^2+10.2x for all positive x. Denote f'(x) to be the derivative of f(x). What is the value of f'(0)?

Question

Define a function

f(x)=2exx2+10.2x f(x) = 2e^x - x^2 + 10.2x

for all positive x.

Denote f(x) f'(x) to be the derivative of f(x) f(x) .

What is the value of f(0) f'(0) ?

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Solution

To find the derivative of the function f(x) = 2e^x - x^2 + 10.2x, we need to apply the rules of differentiation to each term separately.

The derivative of 2e^x is 2e^x, because the derivative of e^x is e^x.

The derivative of -x^2 is -2x, by the power rule of differentiation.

The derivative of 10.2x is 10.2, because the derivative of x is 1.

So, the derivative of the function f(x) is f'(x) = 2e^x - 2x + 10.2.

To find the value of f'(0), we substitute x = 0 into the derivative function:

f'(0) = 2e^0 - 20 + 10.2 = 21 - 0 + 10.2 = 2 + 10.2 = 12.2.

This problem has been solved

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