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Define f, g : R → R by f (x) = (x − 2)2 andg(x) =1 if x > 0,0 if x = 0,−1 if x < 0.Calculatelimx→2 g(f (x)) and g limx→2 f (x)

Question

Define f, g : R → R by

f (x) = (x − 2)²
and
g(x) =
\begin{cases}
1 & \text{if } x > 0,
0 & \text{if } x = 0,
-1 & \text{if } x < 0.
\end{cases}

Calculate
limx2g(f(x)) \lim_{x \to 2} g(f (x))

and
glimx2f(x) g \lim_{x \to 2} f (x)

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Solution

First, let's calculate the limit of f(x) as x approaches 2.

lim(x→2) f(x) = lim(x→2) (x - 2)^2

As x approaches 2, (x - 2)^2 approaches 0. So, lim(x→2) f(x) = 0.

Now, let's calculate g(f(x)) as x approaches 2.

g(f(x)) = g((x - 2)^2)

We know that as x approaches 2, (x - 2)^2 (which is f(x)) approaches 0. So, we need to find the value of g at 0.

From the definition of g, we know that g(0) = 0. So, g(f(x)) = 0 as x approaches 2.

Therefore, lim(x→2) g(f(x)) = 0.

Finally, let's calculate g(lim(x→2) f(x)).

We already know that lim(x→2) f(x) = 0. So, we need to find the value of g at 0.

From the definition of g, we know that g(0) = 0.

Therefore, g(lim(x→2) f(x)) = 0.

So, both lim(x→2) g(f(x)) and g(lim(x→2) f(x)) are equal to 0.

This problem has been solved

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