Find the image of (12,3√2)(12,32) under the rotation Rπ/6𝑅𝜋/6 through an anticlockwise angle of π6𝜋6 in R2
Question
Solution 1
To find the image of a point under a rotation in R2, we can use the rotation matrix. The rotation matrix for a counterclockwise rotation of θ is given by:
[cos(θ) -sin(θ)]
[sin(θ) cos(θ)]
Here, θ = π/6. So, the rotation matrix is:
[cos(π/6) -sin(π/6)]
[sin(π/6) cos(π/6)]
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