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In a transistor amplifier, if the base-emitter junction is open, the collector voltage is(a) 𝑉𝐶𝐶 (b) 0V (c) Floating (d) 0.2V

Question

In a transistor amplifier, if the base-emitter junction is open, the collector voltage is

(a) 𝑉𝐶𝐶
(b) 0V
(c) Floating
(d) 0.2V

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Solution

In a transistor amplifier, if the base-emitter junction is open, the collector voltage is (c) Floating.

Here's why:

A transistor amplifier works on the principle of using a small input current to control a larger output current. The base-emitter junction is crucial for this operation. If this junction is open, it means there is no base current.

Without base current, the transistor is in cutoff mode, which means it's not conducting. In this state, the collector current is also zero.

However, the collector voltage isn't necessarily zero or VCC. Instead, it's "floating". This means it's not connected to any voltage or ground, and its value is undefined. It could pick up stray voltages from the surrounding environment, but it's not tied to a specific value.

This problem has been solved

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