The maximum or minimum of a quadratic function f(x) = ax^2 + bx + c is achieved at the vertex of the parabola represented by the function. The x-coordinate of the vertex (h) can be found using the formula h = -b/(2a).

Given the function f(x) = -2x^2 + 8.9x - 1.8, we can identify a = -2 and b = 8.9.

Substituting these values into the formula, we get:

h = -8.9/(2*-2) = 2.225

So, the value of x at which the function achieves its maximum is 2.23 (rounded to two decimal places).

Question

The maximum or minimum of a quadratic function f(x) = ax^2 + bx + c is achieved at the vertex of the parabola represented by the function. The x-coordinate of the vertex (h) can be found using the formula h = -b/(2a).

Given the function f(x) = -2x^2 + 8.9x - 1.8, we can identify a = -2 and b = 8.9.

Substituting these values into the formula, we get:

h = -8.9/(2*-2) = 2.225

So, the value of x at which the function achieves its maximum is 2.23 (rounded to two decimal places).

Knowee AI · Accepted Answer

The maximum or minimum of a quadratic function f(x) = ax^2 + bx + c is achieved at the vertex of the parabola represented by the function. The x-coordinate of the vertex (h) can be found using the formula h = -b/(2a).

Given the function f(x) = -2x^2 + 8.9x - 1.8, we can identify a = -2 and b = 8.9.

Substituting these values into the formula, we get:

h = -8.9/(2*-2) = 2.225

So, the value of x at which the function achieves its maximum is 2.23 (rounded to two decimal places).

What is the value of x, at which the quadratic function f(x)=-2x^2+8.9x-1.8 achieves its maximum? Round your answer to 2 decimal places.

Question

What is the value of x, at which the quadratic function $f(x) = -2x^2 + 8.9x - 1.8$ achieves its maximum?

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