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A steel rod has a length of exactly 20 cm at 30◦C. How much longer is it at50◦C? [Use αSteel = 11 × 10−6/ C◦.

Question

A steel rod has a length of exactly 20 cm at 30°C. How much longer is it at 50°C?

[Use αSteel=11×106/°C \alpha_{Steel} = 11 \times 10^{-6} / °C ]

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Solution

To find out how much longer the steel rod is at 50°C compared to its length at 30°C, we can use the coefficient of linear expansion for steel, which is given as αSteel = 11 × 10^(-6)/°C.

Step 1: Calculate the change in temperature The change in temperature is given by ΔT = T2 - T1, where T2 is the final temperature (50°C) and T1 is the initial temperature (30°C). ΔT = 50°C - 30°C ΔT = 20°C

Step 2: Calculate the change in length The change in length is given by ΔL = αSteel * L * ΔT, where αSteel is the coefficient of linear expansion for steel, L is the initial length of the rod (20 cm), and ΔT is the change in temperature. ΔL = (11 × 10^(-6)/°C) * (20 cm) * (20°C) ΔL = 0.00022 cm

Therefore, the steel rod is 0.00022 cm longer at 50°C compared to its length at 30°C.

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