The total number of protons in 10 gm of calcium carbonate is (No = 6.023 × 1023) 1.5057 × 1024 2.0478 × 1024 3.0115 × 1024 14.0956 × 1024

To answer this question, we need to follow these steps:

1. First, we need to know the molecular weight of calcium carbonate (CaCO3). The atomic weights of Calcium (Ca), Carbon (C), and Oxygen (O) are approximately 40.08, 12.01, and 16.00 respectively. So, the molecular weight of CaCO3 = 40.08 + 12.01 + (3*16.00) = 100.09 g/mol.

2. Next, we calculate the number of moles in 10g of calcium carbonate. The number of moles = mass / molar mass = 10g / 100.09 g/mol = 0.09991 mol.

3. Now, we find the total number of molecules in 10g of calcium carbonate. We use Avogadro's number (6.023 x 10^23) for this. Total molecules = number of moles * Avogadro's number = 0.09991 mol * 6.023 x 10^23 = 6.0115 x 10^22 molecules.

4. Each molecule of calcium carbonate (CaCO3) contains one atom of calcium (20 protons), one atom of carbon (6 protons), and three atoms of oxygen (8 protons each, so 24 protons total). So, each molecule contains 20 + 6 + 24 = 50 protons.

5. Finally, we find the total number of protons in 10g of calcium carbonate. Total protons = total molecules * protons per molecule = 6.0115 x 10^22 * 50 = 3.00575 x 10^24 protons.

So, the closest answer to the options given is 3.0115 x 10^24.