The slope of a parabola 𝑦=3𝑥2−11𝑥+10y=3x 2 −11x+10 at a point 𝑃P is -5. Find the 𝑦−y− coordinate of the point 𝑃P.
Question
Solution 1
The slope of a parabola given by the equation y = ax^2 + bx + c is given by the derivative of the function, which is 2ax + b.
In this case, the equation of the parabola is y = 3x^2 - 11x + 10. So, the derivative of the function is 2*3x - 11 = 6x - 11.
We are given that the slope of the parabola a Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
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The slope of a parabola 𝑦=3𝑥2−11𝑥+10y=3x 2 −11x+10 at a point 𝑃P is -5. Find the 𝑦−y− coordinate of the point 𝑃P.
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