What's the molarity (M) of table sugar in a 250 mL cup of tea if 7.17 g of sugar was added? Answer to 4 decimal place.Table sugar = C12H22O11 = 342.30 g.mol-1
Question
What's the molarity (M) of table sugar in a 250 mL cup of tea if 7.17 g of sugar was added?
- Answer to 4 decimal place.
- Table sugar = C12H22O11 = 342.30 g/mol
Solution
Step 1: Identify the given values
The mass (m) of C12H22O11 = 7.17 g The molar mass (M) of C12H22O11 = 342.30 g/mol The volume (V) of the solution = 250 mL = 0.250 L (since 1L = 1000mL)
Step 2: Calculate the number of moles (n) of C12H22O11
The formula to calculate the number of moles is:
n = m/M
Substitute the given values into the formula:
n = 7.17 g / 342.30 g/mol = 0.02094 mol
Step 3: Calculate the molarity (M) of the solution
The formula to calculate the molarity is:
M = n/V
Substitute the given values into the formula:
M = 0.02094 mol / 0.250 L = 0.0838 M
So, the molarity of the table sugar in the tea is 0.0838 M.
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