Suppose a code encodes 3 logical qubits into n𝑛 physical qubits, using 8 generators. What is the value of n𝑛 ?
Question
Suppose a code encodes 3 logical qubits into n physical qubits, using 8 generators. What is the value of n ?
Solution
The value of n can be determined using the quantum error correction code formula:
n - k = 2m
where: n = number of physical qubits k = number of logical qubits m = number of generators
In this case, k = 3 (logical qubits) and m = 8 (generators). Substituting these values into the formula gives:
n - 3 = 2 * 8
Solving for n gives:
n = 2 * 8 + 3 n = 16 + 3 n = 19
So, the code encodes 3 logical qubits into 19 physical qubits.
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