Using recursion, debug the following program to find 1+2+...+N, where N is obtained from user.Sample Input:4Sample Output:The result is 10

To debug the program and calculate the sum of numbers from 1 to N using recursion, follow these steps:

1. Start by defining a function called calculateSum that takes an integer parameter N representing the upper limit of the sum.

2. Inside the calculateSum function, add a base case to handle the smallest possible value of N. If N is equal to 1, return 1 as the sum.

3. If the base case is not met, recursively call the calculateSum function with N-1 as the argument and store the result in a variable called partialSum.

4. Finally, return the sum of partialSum and N.

Here is the corrected code:

def calculateSum(N):
    if N == 1:
        return 1
    else:
        partialSum = calculateSum(N-1)
        return partialSum + N

# Get input from the user
N = int(input("Enter a number: "))

# Call the calculateSum function and store the result in a variable
result = calculateSum(N)

# Print the result
print("The result is", result)

Now, when you run the program and provide the input 4, it will correctly calculate the sum of numbers from 1 to 4, which is 10.