How many times is the comparison i >= n performed in the following program?int i = 300, n = 150;main(){ while (i >= n){ i = i-2; n = n+1; }}
Question
How many times is the comparison i >= n performed in the following program?
int i = 300, n = 150;
main() {
while (i >= n) {
i = i - 2;
n = n + 1;
}
}
Solution
The comparison i >= n is performed in each iteration of the while loop. The loop continues as long as i is greater than or equal to n.
Initially, i is 300 and n is 150. In each iteration of the loop, i is decreased by 2 and n is increased by 1.
So, the loop will continue until i is less than n.
To find out how many times the comparison is performed, we need to calculate the number of iterations.
The difference between i and n is 150. In each iteration, this difference is decreased by 3 (because i is decreased by 2 and n is increased by 1).
So, the number of iterations is 150 / 3 = 50.
Therefore, the comparison i >= n is performed 50 times.
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