Assume that the random variable X is normally distributed with mean μ = 120 and standard deviation σ = 13. Find P(X <105).
Question
Solution 1
To find P(X < 105), we first need to convert the raw score of X = 105 to a z-score. The z-score is a measure of how many standard deviations an element is from the mean.
The formula to calculate the z-score is:
Z = (X - μ) / σ
where: X = raw score μ = mean σ = standard deviation
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