Suppose a normal distribution has a mean of 98 and a standard deviation of 6. What is P(x ≥ 86)?
Question
Solution 1
To find P(x ≥ 86), we first need to convert the raw score (x) of 86 to a z-score. The z-score is a measure of how many standard deviations an element is from the mean.
The formula for calculating the z-score is:
Z = (X - μ) / σ
where: X = raw score μ = mean σ = standard deviation
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