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A rocket starts from rest and accelerates to a speed of 200 meters per second in 40 seconds.  What is its acceleration?

Question

A rocket starts from rest and accelerates to a speed of 200 meters per second in 40 seconds.

What is its acceleration?

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Solution

1. Break Down the Problem

To find the acceleration of the rocket, we need to identify the given data and the formula for acceleration. The data given includes:

  • Initial speed (u u ) = 0 m/s (the rocket starts from rest)
  • Final speed (v v ) = 200 m/s
  • Time (t t ) = 40 s

2. Relevant Concepts

The formula to calculate acceleration (a a ) is: a=vut a = \frac{v - u}{t} where:

  • v v is the final velocity,
  • u u is the initial velocity,
  • t t is the time taken.

3. Analysis and Detail

Now we will substitute the known values into the acceleration formula:

  • v=200 v = 200 m/s
  • u=0 u = 0 m/s
  • t=40 t = 40 s

Plugging these values into the formula gives: a=200m/s0m/s40s=200m/s40s=5m/s2 a = \frac{200 \, \text{m/s} - 0 \, \text{m/s}}{40 \, \text{s}} = \frac{200 \, \text{m/s}}{40 \, \text{s}} = 5 \, \text{m/s}^2

4. Verify and Summarize

We have calculated the acceleration as 5m/s2 5 \, \text{m/s}^2 . To verify, we can check if the units are consistent: meters per second squared is indeed the correct unit for acceleration, and the calculations are consistent with the formula used.

Final Answer

The acceleration of the rocket is 5m/s2 5 \, \text{m/s}^2 .

This problem has been solved

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