Determine those values of λ for which the matrix 1 λ 0 3 2 0 1 2 1 is not invertible
Question
Determine those values of for which the matrix
is not invertible.
Solution
A matrix is not invertible (or singular) if and only if its determinant is zero. So, we need to find the values of λ that make the determinant of the matrix zero.
The matrix is:
1 λ 0 3 2 0 1 2 1
The determinant of a 3x3 matrix
a b c d e f g h i
is given by the formula:
a(ei−fh)−b(di−fg)+c(dh−eg)
So, the determinant of our matrix is:
1*(21 - 02) - λ*(31 - 01) + 0*(32 - 11)
Simplify this to:
2 - 3λ
Set the determinant equal to zero and solve for λ:
2 - 3λ = 0 3λ = 2 λ = 2/3
So, the matrix is not invertible for λ = 2/3.
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