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The velocity of the  plane wave sin2 (ωt- βx) isans.ω/2β2ω/βω/βω2/β2 Previous Marked for Review Next

Question

The velocity of the  plane wave sin2(ωtβx) \sin^2 (\omega t - \beta x) is

ω2β \frac{\omega}{2\beta}
ωβ \frac{\omega}{\beta}
ωβ \frac{\omega}{\beta}
ω2β2 \frac{\omega^2}{\beta^2}

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Solution

The velocity of a plane wave is given by the formula v = ω/β.

Here's the step by step solution:

  1. The general equation for a plane wave is given by y = A sin(ωt - βx + φ), where:

    • A is the amplitude of the wave
    • ω is the angular frequency
    • t is the time
    • β is the wave number
    • x is the position
    • φ is the phase constant
  2. In the given wave equation sin2 (ωt- βx), ω is the angular frequency and β is the wave number.

  3. The velocity of the wave (v) is given by the ratio of the angular frequency to the wave number, i.e., v = ω/β.

So, the velocity of the plane wave sin2 (ωt- βx) is ω/β.

This problem has been solved

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