A Helium atom contains one electron in the n = 6 energy orbital. Calculate the energy of the electron. Give your answer in SI units with the correct sign.
Question
Solution 1
The energy of an electron in an atom is given by the formula:
E = -13.6 * Z^2 / n^2 eV
where:
- E is the energy of the electron,
- Z is the atomic number of the atom (for helium, Z = 2),
- n is the principal quantum number (in this case, n = 6).
Substituting the values into the formula, we get:
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