What will the below Python code will return?a=[10,50,89]b='123'for i in a:    b=b+" " + iprint(b)123105089123123 10 50 89Error

To understand the behavior of the provided Python code, let's break it down step by step.

Code Breakdown

1. Initialization:

   • a = [10, 50, 89]: A list containing three integers.
   • b = '123': A string initialized with the value "123".

2. Looping through the list:

   • The for loop iterates over each element in the list a.

3. Concatenation:

   • During each iteration, the current integer i from list a is converted to a string and concatenated to the string b with a preceding space (i.e., b = b + " " + str(i)).

4. Printing:

   • After concatenating the elements, the final value of b is printed out.

Detailed Analysis

• When i = 10:

  • b becomes '123' + ' ' + '10' → b = '123 10'.

• When i = 50:

  • b becomes '123 10' + ' ' + '50' → b = '123 10 50'.

• When i = 89:

  • b becomes '123 10 50' + ' ' + '89' → b = '123 10 50 89'.

Finally, after the loop finishes, the print statement outputs the value of b.

Final Answer

The code will return:

'123 10 50 89'