To solve this problem, we can use the formula for distance in uniformly accelerated motion:

d = vit + 0.5at^2

where:
- d is the distance,
- vi is the initial velocity,
- a is the acceleration, and
- t is the time.

In this case, the airplane starts from rest, so the initial velocity (vi) is 0. The acceleration (a) is 3.20 m/s^2 and the time (t) is 32.8 s. Substituting these values into the formula gives:

d = 0*(32.8 s) + 0.5*(3.20 m/s^2)*(32.8 s)^2

Solving this equation gives the distance traveled before takeoff.

Question

To solve this problem, we can use the formula for distance in uniformly accelerated motion:

d = vit + 0.5at^2

where:
- d is the distance,
- vi is the initial velocity,
- a is the acceleration, and
- t is the time.

In this case, the airplane starts from rest, so the initial velocity (vi) is 0. The acceleration (a) is 3.20 m/s^2 and the time (t) is 32.8 s. Substituting these values into the formula gives:

d = 0*(32.8 s) + 0.5*(3.20 m/s^2)*(32.8 s)^2

Solving this equation gives the distance traveled before takeoff.

Knowee AI · Accepted Answer

To solve this problem, we can use the formula for distance in uniformly accelerated motion:

d = vit + 0.5at^2

where:
- d is the distance,
- vi is the initial velocity,
- a is the acceleration, and
- t is the time.

In this case, the airplane starts from rest, so the initial velocity (vi) is 0. The acceleration (a) is 3.20 m/s^2 and the time (t) is 32.8 s. Substituting these values into the formula gives:

d = 0*(32.8 s) + 0.5*(3.20 m/s^2)*(32.8 s)^2

Solving this equation gives the distance traveled before takeoff.

An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff.

Question

An airplane accelerates down a runway at 3.20 m/s² for 32.8 s until it finally lifts off the ground. Determine the distance traveled before takeoff.

Solution

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