What is the velocity of an object accelerating at −25.0m/s 2 after 3.0s when it is initially moving at 30.0m/s?
Question
What is the velocity of an object accelerating at −25.0 m/s²
after 3.0 s
when it is initially moving at 30.0 m/s
?
Solution
Sure, here's how you can calculate the velocity of the object:
Step 1: Understand the given values. The initial velocity (u) = 30.0 m/s The acceleration (a) = -25.0 m/s² The time (t) = 3.0 s
Step 2: Use the formula for velocity when acceleration and time are known. The formula is: v = u + at
Step 3: Substitute the given values into the formula. v = 30.0 m/s + (-25.0 m/s² * 3.0 s)
Step 4: Solve the equation. v = 30.0 m/s - 75.0 m/s v = -45.0 m/s
So, the velocity of the object after 3.0 seconds is -45.0 m/s. The negative sign indicates that the object is moving in the opposite direction to the initial direction.
Similar Questions
The velocity changes from 35m/s to 60m/s in 3 seconds. What is its acceleration?
What is the acceleration of an object that is moving at 45m/s initially, 36m/s after 2.0s and 27m/s after 4.0s?
A car accelerates at a constant rate from 16 m/s to 25 m/s in 3.0 s. What is itsacceleration in m/s2?
What is the acceleration of an object that is initially moving at 10.5m/s and is moving at 13.5m/s after 2.0s?
A car accelerates from 10.0 m/s to 30.0 m/s at a rate of 3.00 m/s2.How far does the car travel while accelerating?Express your answer in meters.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.