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What will be the output of the following program on execution?a=0b=5x=(a&b)|(a&a)|(a|b)print("x")150None of the above

Question

What will be the output of the following program on execution?

 a=0
 b=5
 x=(a&b)|(a&a)|(a|b)
 print("x")
  1. 150
  2. None of the above
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Solution

The output of the program will be 5. Here's why:

The program is written in Python and uses bitwise operators.

  1. a & b is a bitwise AND operation. It will compare the binary representation of a and b. Since a is 0, the result will be 0 because anything AND 0 is 0.

  2. a & a is also a bitwise AND operation. Since both values are 0, the result will be 0.

  3. a | b is a bitwise OR operation. It will compare the binary representation of a and b. Since a is 0 and b is 5, the result will be 5 because 0 OR anything is that number.

  4. The final operation is x = (a & b) | (a & a) | (a | b). Substituting the results from the previous steps, we get x = 0 | 0 | 5, which equals 5.

So, the print statement will output 5.

This problem has been solved

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