What will be the output of the following program on execution?a=0b=5x=(a&b)|(a&a)|(a|b)print("x")150None of the above
Question
What will be the output of the following program on execution?
a=0
b=5
x=(a&b)|(a&a)|(a|b)
print("x")
- 150
- None of the above
Solution
The output of the program will be 5. Here's why:
The program is written in Python and uses bitwise operators.
-
a & b
is a bitwise AND operation. It will compare the binary representation of a and b. Since a is 0, the result will be 0 because anything AND 0 is 0. -
a & a
is also a bitwise AND operation. Since both values are 0, the result will be 0. -
a | b
is a bitwise OR operation. It will compare the binary representation of a and b. Since a is 0 and b is 5, the result will be 5 because 0 OR anything is that number. -
The final operation is
x = (a & b) | (a & a) | (a | b)
. Substituting the results from the previous steps, we getx = 0 | 0 | 5
, which equals 5.
So, the print statement will output 5.
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