The code you provided will not compile correctly because it is trying to assign an integer value to a pointer variable.

Here's the step by step explanation:

1. `int n = 98;` This line declares an integer variable `n` and initializes it with the value `98`.

2. `int *p = &n;` This line declares a pointer to an integer `p` and assigns it the address of `n`. So, `p` is now pointing to `n`.

3. `p = 402;` This line is trying to assign the integer value `402` to the pointer `p`. This is not allowed because `p` is a pointer and it should be assigned an address of a variable, not a direct integer value.

So, this code will result in a compilation error. If the code was corrected to `*p = 402;` then the value of `n` would be `402` because `p` is pointing to `n` and we are changing the value at the address `p` is pointing to.

Question

The code you provided will not compile correctly because it is trying to assign an integer value to a pointer variable.

Here's the step by step explanation:

1. `int n = 98;` This line declares an integer variable `n` and initializes it with the value `98`.

2. `int *p = &n;` This line declares a pointer to an integer `p` and assigns it the address of `n`. So, `p` is now pointing to `n`.

3. `p = 402;` This line is trying to assign the integer value `402` to the pointer `p`. This is not allowed because `p` is a pointer and it should be assigned an address of a variable, not a direct integer value.

So, this code will result in a compilation error. If the code was corrected to `*p = 402;` then the value of `n` would be `402` because `p` is pointing to `n` and we are changing the value at the address `p` is pointing to.

Knowee AI · Accepted Answer

The code you provided will not compile correctly because it is trying to assign an integer value to a pointer variable.

Here's the step by step explanation:

1. `int n = 98;` This line declares an integer variable `n` and initializes it with the value `98`.

2. `int *p = &n;` This line declares a pointer to an integer `p` and assigns it the address of `n`. So, `p` is now pointing to `n`.

3. `p = 402;` This line is trying to assign the integer value `402` to the pointer `p`. This is not allowed because `p` is a pointer and it should be assigned an address of a variable, not a direct integer value.

So, this code will result in a compilation error. If the code was corrected to `*p = 402;` then the value of `n` would be `402` because `p` is pointing to `n` and we are changing the value at the address `p` is pointing to.

What is the value of n after the following code is executed?int n = 98;int *p = &n;p = 402;

Question

What is the value of `n` after the following code is executed?

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