1 L of 1 M CuSO solution is electrolysed.After passing 2F charge, the molarity of CuSOwill be (Assume no change in volume) :
Question
Solution 1
To find the molarity of CuSO4 after passing 2F charge, we can use the formula:
M1V1 = M2V2
Given: Initial molarity (M1) = 1 M Initial volume (V1) = 1 L Final volume (V2) = 1 L (assuming no change in volume) Charge passed (Q) = 2F
Since 1 mole of CuSO4 corresponds to 2 moles of electrons (2F), we Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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