46g of Sodium reacted with 18g of Oxygen. Which law can be used to calculate how much Sodium Oxide would be produced?

Law of Conservation of Mass

1. Definition: The Law of Conservation of Mass states that in a chemical reaction, the mass of the reactants must equal the mass of the products. This law implies that the total mass before the reaction is equal to the total mass after the reaction.

2. Application: In your scenario, when sodium (Na) reacts with oxygen (O$_2$), it forms sodium oxide (Na$_2$O). We can calculate how much sodium oxide will be produced by first determining the total mass of the reactants and then applying the law to find the mass of the products.

3. Calculation: The mass of sodium (Na) is 46 g and the mass of oxygen (O$_2$) is 18 g, so the total mass of reactants is: $\text{Total mass of reactants} = 46 \text{ g (Na)} + 18 \text{ g (O}_2\text{)} = 64 \text{ g}$ According to the law, the mass of sodium oxide produced will also be 64 g.

Final Answer

The Law of Conservation of Mass can be used to calculate that 64 g of sodium oxide would be produced from the reaction of 46 g of sodium with 18 g of oxygen.