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We know that the stone's velocity was −152 ft/s when it hit the ground. Therefore, since v(t) = −32t, the time when the stone hit the ground wast = s.

Question

We know that the stone's velocity was −152 ft/s when it hit the ground. Therefore, since

v(t) = −32t, the time when the stone hit the ground was

t = s.

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Solution

Break Down the Problem

  1. We are given the velocity function of the stone as v(t)=32t v(t) = -32t .
  2. We need to find the time t t when the velocity v(t) v(t) is equal to −152 ft/s.

Relevant Concepts

  1. The relationship between the velocity and time is given by the equation v(t)=32t v(t) = -32t .
  2. To find t t , we will set v(t)=152 v(t) = -152 and solve for t t .

Analysis and Detail

  1. Set the velocity equal to -152: 32t=152 -32t = -152
  2. To solve for t t , divide both sides by -32: t=15232 t = \frac{-152}{-32}
  3. Simplifying this fraction: t=15232 t = \frac{152}{32}
  4. Reduce the fraction: t=194 or 4.75 seconds t = \frac{19}{4} \text{ or } 4.75 \text{ seconds}

Verify and Summarize

  1. The calculations show that t=4.75 t = 4.75 .
  2. We can double-check by substituting t t back into the velocity equation.
    • If t=4.75 t = 4.75 : v(4.75)=32×4.75=152 ft/s v(4.75) = -32 \times 4.75 = -152 \text{ ft/s} This matches the condition when the stone hit the ground.

Final Answer

The time when the stone hit the ground was t=4.75 t = 4.75 seconds.

This problem has been solved

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