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Find average density of the sphere of radius ๐‘Ž whose density at a distance๐‘Ÿ from the centre of the sphere is ๐œŒ = ๐œŒ0 [1 + ๐‘˜ ๐‘Ÿ3๐‘Ž3

Question

Find average density of the sphere of radius a a whose density at a distance r r from the centre of the sphere is ( \rho = \rho_0 \left[1 + k \frac{r^3}{a^3}\right] \

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Solution

To find the average density of the sphere, we need to integrate the density function over the entire volume of the sphere and then divide by the total volume.

Step 1: Determine the volume of the sphere. The volume of a sphere with radius ๐‘Ž is given by the formula V = (4/3)ฯ€๐‘Ž^3.

Step 2: Set up the integral for the average density. The average density (๐œŒ_avg) is given by the equation: ๐œŒ_avg = (1/V) โˆซ๐œŒ dV

Step 3: Express the density function in terms of ๐‘Ÿ. Given that ๐œŒ = ๐œŒ0 [1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3], we can substitute this expression into the integral: ๐œŒ_avg = (1/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] dV

Step 4: Convert the integral to spherical coordinates. Since we are dealing with a sphere, it is more convenient to use spherical coordinates. The volume element in spherical coordinates is given by dV = ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ d๐œƒ d๐œ™, where ๐œƒ ranges from 0 to ๐œ‹ and ๐œ™ ranges from 0 to 2๐œ‹.

Step 5: Evaluate the integral. Substitute the expression for dV and the limits of integration into the integral: ๐œŒ_avg = (1/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ d๐œƒ d๐œ™

Integrate with respect to ๐‘Ÿ from 0 to ๐‘Ž, ๐œƒ from 0 to ๐œ‹, and ๐œ™ from 0 to 2๐œ‹: ๐œŒ_avg = (1/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ d๐œƒ d๐œ™ = (1/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ โˆซ๐œƒ d๐œƒ โˆซ๐œ™ d๐œ™

Evaluate the integrals: ๐œŒ_avg = (1/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ โˆซ๐œƒ d๐œƒ โˆซ๐œ™ d๐œ™ = (1/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ [-cos(๐œƒ)] [2๐œ‹]

Simplify the expression: ๐œŒ_avg = (1/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ [-cos(๐œƒ)] [2๐œ‹] = (2๐œ‹/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ [-cos(๐œƒ)]

Step 6: Evaluate the remaining integral. Integrate with respect to ๐‘Ÿ from 0 to ๐‘Ž: ๐œŒ_avg = (2๐œ‹/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ [-cos(๐œƒ)] = (2๐œ‹/V) โˆซ[๐œŒ0 (1 + ๐‘˜(๐‘Ÿ/๐‘Ž)^3)] ๐‘Ÿ^2 sin(๐œƒ) d๐‘Ÿ [-cos(๐œƒ)] evaluated from 0 to ๐‘Ž

Evaluate the integral at the upper limit ๐‘Ž and subtract the value at the lower limit 0: ๐œŒ_avg = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜(๐‘Ž/๐‘Ž)^3)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated from 0 to ๐‘Ž

Simplify the expression: ๐œŒ_avg = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated from 0 to ๐‘Ž

Step 7: Calculate the average density. Substitute the values into the expression: ๐œŒ_avg = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated from 0 to ๐‘Ž = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated at ๐‘Ž minus evaluated at 0

Evaluate the expression at ๐‘Ž: ๐œŒ_avg = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated at ๐‘Ž = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated at ๐‘Ž

Evaluate the expression at 0: ๐œŒ_avg = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated at ๐‘Ž = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated at ๐‘Ž - (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] 0^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated at 0

Simplify the expression: ๐œŒ_avg = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated at ๐‘Ž - (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] 0^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated at 0 = (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] ๐‘Ž^2 sin(๐œƒ) [-cos(๐œƒ)] evaluated at ๐‘Ž - (2๐œ‹/V) [๐œŒ0 (1 + ๐‘˜)] 0^2 sin

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