Find average density of the sphere of radius ๐ whose density at a distance๐ from the centre of the sphere is ๐ = ๐0 [1 + ๐ ๐3๐3
Question
Find average density of the sphere of radius whose density at a distance from the centre of the sphere is ( \rho = \rho_0 \left[1 + k \frac{r^3}{a^3}\right] \
Solution
To find the average density of the sphere, we need to integrate the density function over the entire volume of the sphere and then divide by the total volume.
Step 1: Determine the volume of the sphere. The volume of a sphere with radius ๐ is given by the formula V = (4/3)ฯ๐^3.
Step 2: Set up the integral for the average density. The average density (๐_avg) is given by the equation: ๐_avg = (1/V) โซ๐ dV
Step 3: Express the density function in terms of ๐. Given that ๐ = ๐0 [1 + ๐(๐/๐)^3], we can substitute this expression into the integral: ๐_avg = (1/V) โซ[๐0 (1 + ๐(๐/๐)^3)] dV
Step 4: Convert the integral to spherical coordinates. Since we are dealing with a sphere, it is more convenient to use spherical coordinates. The volume element in spherical coordinates is given by dV = ๐^2 sin(๐) d๐ d๐ d๐, where ๐ ranges from 0 to ๐ and ๐ ranges from 0 to 2๐.
Step 5: Evaluate the integral. Substitute the expression for dV and the limits of integration into the integral: ๐_avg = (1/V) โซ[๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) d๐ d๐ d๐
Integrate with respect to ๐ from 0 to ๐, ๐ from 0 to ๐, and ๐ from 0 to 2๐: ๐_avg = (1/V) โซ[๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) d๐ d๐ d๐ = (1/V) โซ[๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) d๐ โซ๐ d๐ โซ๐ d๐
Evaluate the integrals: ๐_avg = (1/V) โซ[๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) d๐ โซ๐ d๐ โซ๐ d๐ = (1/V) โซ[๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) d๐ [-cos(๐)] [2๐]
Simplify the expression: ๐_avg = (1/V) โซ[๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) d๐ [-cos(๐)] [2๐] = (2๐/V) โซ[๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) d๐ [-cos(๐)]
Step 6: Evaluate the remaining integral. Integrate with respect to ๐ from 0 to ๐: ๐_avg = (2๐/V) โซ[๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) d๐ [-cos(๐)] = (2๐/V) โซ[๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) d๐ [-cos(๐)] evaluated from 0 to ๐
Evaluate the integral at the upper limit ๐ and subtract the value at the lower limit 0: ๐_avg = (2๐/V) [๐0 (1 + ๐(๐/๐)^3)] ๐^2 sin(๐) [-cos(๐)] evaluated from 0 to ๐
Simplify the expression: ๐_avg = (2๐/V) [๐0 (1 + ๐)] ๐^2 sin(๐) [-cos(๐)] evaluated from 0 to ๐
Step 7: Calculate the average density. Substitute the values into the expression: ๐_avg = (2๐/V) [๐0 (1 + ๐)] ๐^2 sin(๐) [-cos(๐)] evaluated from 0 to ๐ = (2๐/V) [๐0 (1 + ๐)] ๐^2 sin(๐) [-cos(๐)] evaluated at ๐ minus evaluated at 0
Evaluate the expression at ๐: ๐_avg = (2๐/V) [๐0 (1 + ๐)] ๐^2 sin(๐) [-cos(๐)] evaluated at ๐ = (2๐/V) [๐0 (1 + ๐)] ๐^2 sin(๐) [-cos(๐)] evaluated at ๐
Evaluate the expression at 0: ๐_avg = (2๐/V) [๐0 (1 + ๐)] ๐^2 sin(๐) [-cos(๐)] evaluated at ๐ = (2๐/V) [๐0 (1 + ๐)] ๐^2 sin(๐) [-cos(๐)] evaluated at ๐ - (2๐/V) [๐0 (1 + ๐)] 0^2 sin(๐) [-cos(๐)] evaluated at 0
Simplify the expression: ๐_avg = (2๐/V) [๐0 (1 + ๐)] ๐^2 sin(๐) [-cos(๐)] evaluated at ๐ - (2๐/V) [๐0 (1 + ๐)] 0^2 sin(๐) [-cos(๐)] evaluated at 0 = (2๐/V) [๐0 (1 + ๐)] ๐^2 sin(๐) [-cos(๐)] evaluated at ๐ - (2๐/V) [๐0 (1 + ๐)] 0^2 sin
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