A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
Question
A is two years older than B who is twice as old as C.
If the total of the ages of A, B and C be 27, then how old is B?
Solution
Let's denote the age of C as x.
According to the problem, B is twice as old as C, so B = 2x.
A is two years older than B, so A = 2x + 2.
The total age of A, B, and C is 27, so we can set up the following equation:
A + B + C = 27
Substituting the expressions for A, B, and C from above, we get:
(2x + 2) + 2x + x = 27
Solving this equation, we get:
5x + 2 = 27
Subtract 2 from both sides:
5x = 25
Divide both sides by 5:
x = 5
So, C is 5 years old.
Since B is twice as old as C, B = 2 * 5 = 10 years old.
So, B is 10 years old.
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