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Average age of A and B is 30 years, that of B and C is 32 years and the average age of C and A is 34 years.The age of C is3334 years35 years36 years

Question

Average age of A and B is 30 years, that of B and C is 32 years and the average age of C and A is 34 years.

The age of C is

  • 33 years
  • 34 years
  • 35 years
  • 36 years
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Solution

Given that the average age of A and B is 30 years, we can write this as:

(A + B)/2 = 30 => A + B = 60 ----(1)

Similarly, given that the average age of B and C is 32 years, we can write this as:

(B + C)/2 = 32 => B + C = 64 ----(2)

And given that the average age of C and A is 34 years, we can write this as:

(C + A)/2 = 34 => C + A = 68 ----(3)

Now, if we add equations (1) and (2), we get:

A + B + B + C = 60 + 64 => A + 2B + C = 124 ----(4)

And if we subtract equation (3) from equation (4), we get:

A + 2B + C - (C + A) = 124 - 68 => B = 56

Substituting B = 56 in equation (2), we get:

56 + C = 64 => C = 64 - 56 => C = 8

So, the age of C is 8 years.

This problem has been solved

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