The program is written in Python and it takes three inputs from the user: a, b, and c. It then enters a while loop where it checks if 'a' is less than 'b'. If 'a' is less than 'b', it prints the value of 'a'. Then it checks if 'a' is greater than 'c'. If 'a' is greater than 'c', it breaks the loop. Otherwise, it increments 'a' by 2 and the loop continues.

Given the input 2, 20, 2, the output will be:

2
4
6
8
10
12
14
16
18

This is because the loop will continue to print and increment 'a' by 2 as long as 'a' is less than 'b' (20 in this case). The check if 'a' is greater than 'c' will never be true because 'c' is 2 and 'a' starts from 2 and only increases. Therefore, the loop will not break until 'a' is no longer less than 'b'.

Question

The program is written in Python and it takes three inputs from the user: a, b, and c. It then enters a while loop where it checks if 'a' is less than 'b'. If 'a' is less than 'b', it prints the value of 'a'. Then it checks if 'a' is greater than 'c'. If 'a' is greater than 'c', it breaks the loop. Otherwise, it increments 'a' by 2 and the loop continues.

Given the input 2, 20, 2, the output will be:

2
4
6
8
10
12
14
16
18

This is because the loop will continue to print and increment 'a' by 2 as long as 'a' is less than 'b' (20 in this case). The check if 'a' is greater than 'c' will never be true because 'c' is 2 and 'a' starts from 2 and only increases. Therefore, the loop will not break until 'a' is no longer less than 'b'.

Knowee AI · Accepted Answer

The program is written in Python and it takes three inputs from the user: a, b, and c. It then enters a while loop where it checks if 'a' is less than 'b'. If 'a' is less than 'b', it prints the value of 'a'. Then it checks if 'a' is greater than 'c'. If 'a' is greater than 'c', it breaks the loop. Otherwise, it increments 'a' by 2 and the loop continues.

Given the input 2, 20, 2, the output will be:

2
4
6
8
10
12
14
16
18

This is because the loop will continue to print and increment 'a' by 2 as long as 'a' is less than 'b' (20 in this case). The check if 'a' is greater than 'c' will never be true because 'c' is 2 and 'a' starts from 2 and only increases. Therefore, the loop will not break until 'a' is no longer less than 'b'.

Type the program's outputa = int(input())b = int(input())c = int(input())while a < b: print(a) if a > c: break a += 2 Input2202Output

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Type the program's output

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