Find all solutions if 0 ≤ x < 2𝜋. Use exact values only. (Enter your answers as a comma-separated list.)cos 2x cos x − sin 2x sin x = 22x =
Question
Find all solutions if . Use exact values only. (Enter your answers as a comma-separated list.)
Solution
The equation you've given is a form of the cosine double angle identity. The identity is cos(2x) = cos²(x) - sin²(x), which can also be written as cos(2x) = 2cos²(x) - 1 or cos(2x) = 1 - 2sin²(x). However, the equation you've given seems to be incomplete or incorrectly written.
The expression "cos 2x cos x − sin 2x sin x" is equivalent to cos(x + 2x) = cos(3x) using the sum-to-product identities. But the equation "cos 3x = 22x" doesn't make sense because the range of the cosine function is -1 to 1, and 22x will exceed that range for any x > 0.045.
Could you please check the equation and provide the correct one?
Similar Questions
Find all solutions if 0 ≤ x < 2𝜋. Use exact values only. (Enter your answers as a comma-separated list.)cos 2x cos x − sin 2x sin x = 22x =
The number of solutions of the equation sin2x−2cosx+4sinx=4 in the interval [0,5π] is:
Find exact solutions of the equation cos(𝑥)=1−cos(𝑥) for 𝑥 in the interval [0,2𝜋].
Solve the trigonometric equation6cos(2𝑡)−2=4to find an exact solution on the interval [0,𝜋]
Find the critical numbers of the function. (Enter your answers as a comma-separated list.)h(x) = sin2(x) + cos(x) 0 < x < 2𝜋
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.