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Find all solutions if 0 ≤ x < 2𝜋. Use exact values only. (Enter your answers as a comma-separated list.)cos 2x cos x − sin 2x sin x = 22x =

Question

Find all solutions if 0x<2π 0 \leq x < 2\pi . Use exact values only. (Enter your answers as a comma-separated list.)

cos2xcosxsin2xsinx=2 \cos 2x \cos x - \sin 2x \sin x = 2

2x= 2x =

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Solution

The equation you've given is a form of the cosine double angle identity. The identity is cos(2x) = cos²(x) - sin²(x), which can also be written as cos(2x) = 2cos²(x) - 1 or cos(2x) = 1 - 2sin²(x). However, the equation you've given seems to be incomplete or incorrectly written.

The expression "cos 2x cos x − sin 2x sin x" is equivalent to cos(x + 2x) = cos(3x) using the sum-to-product identities. But the equation "cos 3x = 22x" doesn't make sense because the range of the cosine function is -1 to 1, and 22x will exceed that range for any x > 0.045.

Could you please check the equation and provide the correct one?

This problem has been solved

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