Count the number of tokens in the following C statement: scanf("i=%d", &i);Question 6Answera.6b.9c.8d.7

1. Break Down the Problem

To count the number of tokens in the C statement scanf("i=%d", &i);, we need to identify the individual components that constitute the statement.

2. Relevant Concepts

In C, a token is a basic building block of the program, which can include keywords, identifiers, constants, string literals, and operators.

3. Analysis and Detail

Let's analyze the given statement:

• scanf: This is a function name (1 token).
• (: This is an opening parenthesis (1 token).
• "i=%d": This is a string literal (1 token).
• ,: This is a comma (1 token).
• &i: Here, & is an operator, and i is an identifier (2 tokens).
• ): This is a closing parenthesis (1 token).
• ;: This is a semicolon (1 token).

Now, let's count these tokens:

1. scanf (1 token)
2. ( (1 token)
3. "i=%d" (1 token)
4. , (1 token)
5. & (1 token) and i (1 token) = 2 tokens
6. ) (1 token)
7. ; (1 token)

4. Verify and Summarize

Now summing up the tokens identified:

• 1 (scanf)
• 1 (open parenthesis)
• 1 (string literal)
• 1 (comma)
• 2 (address operator and identifier)
• 1 (close parenthesis)
• 1 (semicolon)

Total: 1 + 1 + 1 + 1 + 2 + 1 + 1 = 8 tokens.

Final Answer

The number of tokens in the statement scanf("i=%d", &i); is 8.

Thus, the correct answer is c. 8.