The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i); in c

To understand the output of the given code snippet, we need to analyze the expression being printed in the printf function.

1. Break Down the Problem

The function printf is trying to print three integers:

• i: which is initially 5.
• i++: post-increment operation, meaning it will use the current value of i (5) and then increment i by 1.
• ++i: pre-increment operation, which increments i by 1 first before using its value.

2. Relevant Concepts

• Post-increment (i++): Returns the current value of i before incrementing.
• Pre-increment (++i): Increments the value of i first, then returns the new value.

3. Analysis and Detail

1. The initial value of i is 5.
2. When the statement printf("%d %d %d", i, i++, ++i); is executed:
   • The first item i will retrieve the current value of i, which is 5.
   • The second item i++ will use the current value, which is still 5, and after this, i becomes 6.
   • The third item ++i now retrieves the value of i which has been incremented to 6, so ++i will give 7.

Thus, putting these together, we have:

• The first value printed is 5.
• The second value printed is 5 (from i++).
• The third value printed is 7 (after ++i).

4. Verify and Summarize

The values retrieved and printed for each case are:

• First value: 5
• Second value: 5
• Third value: 7

Final Answer

The output of the code will be: 5 5 7.