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A horse accelerates uniformly from 5 to 10 m/s at a rate of 1.25 m/s2.  Calculate the distance which it covers during this time.2 m46.9 m120 m30 m

Question

A horse accelerates uniformly from 5 to 10 m/s at a rate of 1.25 m/s².

Calculate the distance which it covers during this time.

  • 2 m
  • 46.9 m
  • 120 m
  • 30 m
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Solution

To solve this problem, we can use the equation of motion:

v^2 = u^2 + 2as

where: v = final velocity = 10 m/s u = initial velocity = 5 m/s a = acceleration = 1.25 m/s^2 s = distance (which we are trying to find)

Rearranging the equation to find s gives us:

s = (v^2 - u^2) / 2a

Substituting the given values into the equation gives us:

s = (10^2 - 5^2) / (2 * 1.25) s = (100 - 25) / 2.5 s = 75 / 2.5 s = 30 m

So, the horse covers a distance of 30 meters.

This problem has been solved

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