A horse accelerates uniformly from 5 to 10 m/s at a rate of 1.25 m/s2. Calculate the distance which it covers during this time.2 m46.9 m120 m30 m
Question
A horse accelerates uniformly from 5 to 10 m/s at a rate of 1.25 m/s².
Calculate the distance which it covers during this time.
- 2 m
- 46.9 m
- 120 m
- 30 m
Solution
To solve this problem, we can use the equation of motion:
v^2 = u^2 + 2as
where: v = final velocity = 10 m/s u = initial velocity = 5 m/s a = acceleration = 1.25 m/s^2 s = distance (which we are trying to find)
Rearranging the equation to find s gives us:
s = (v^2 - u^2) / 2a
Substituting the given values into the equation gives us:
s = (10^2 - 5^2) / (2 * 1.25) s = (100 - 25) / 2.5 s = 75 / 2.5 s = 30 m
So, the horse covers a distance of 30 meters.
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