A forklift uses 5200 J of energy to lift a 50.0 kg mass to a height of 4.0 m at a constantspeed. What is the efficiency of the forklift?

To solve this problem, we first need to understand the concept of efficiency. Efficiency is the ratio of useful output energy (or power) to the input energy (or power), and it is usually expressed as a percentage.

Step 1: Calculate the work done (output energy) The work done on an object by a force is given by the equation W = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. Here, m = 50.0 kg, g = 9.8 m/s² (approximate value on Earth's surface), and h = 4.0 m.

So, W = 50.0 kg * 9.8 m/s² * 4.0 m = 1960 J.

Step 2: Find the input energy The problem states that the forklift uses 5200 J of energy to lift the mass. So, the input energy is 5200 J.

Step 3: Calculate the efficiency Efficiency = (Output energy / Input energy) * 100% So, Efficiency = (1960 J / 5200 J) * 100% = 37.7%

Therefore, the efficiency of the forklift is 37.7%.