def print_n(s, n): if n > 0: print(s) print_n(s, n-1) return nn = 3while print_n("hi", n): print_n("there!", n) n = 0
Question
Solution 1
The code you've provided is written in Python. It defines a recursive function print_n(s, n) that prints a string s n times. If n is greater than 0, it prints the string and then calls itself with n decremented by 1. The function stops calling itself when n is no longer greater than 0.
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Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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