What is the energy (in eV) of a photon in a monochromatic beam of light with a wavelength of 425.0425.0 nm? (Give your answer to two decimal places) eV
Question
What is the energy (in eV) of a photon in a monochromatic beam of light with a wavelength of 425.0 nm? (Give your answer to two decimal places) eV
Solution
To find the energy of a photon, we can use the formula:
E = hc/λ
where: E is the energy of the photon, h is Planck's constant (4.135667696 x 10^-15 eV*s), c is the speed of light (299792458 m/s), and λ is the wavelength.
However, the wavelength should be in meters for the units to cancel out correctly. Given that the wavelength is 425.0 nm, we need to convert this to meters.
1 nm = 1 x 10^-9 m
So, λ = 425.0 x 10^-9 m
Now we can substitute the values into the formula:
E = (4.135667696 x 10^-15 eV*s * 299792458 m/s) / (425.0 x 10^-9 m)
After calculating the above expression, we get the energy E in electron volts (eV). Round your answer to two decimal places.
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