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The joint probabilities are given in the table. The value of P(Y<=2) is3/161/163/323/64

Question

The joint probabilities are given in the table.

The value of P(Y <= 2) is:

  • 3/16
  • 1/16
  • 3/32
  • 3/64
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Solution

To find P(Y2) P(Y \leq 2) using the joint probabilities from the provided table, we can outline our approach as follows:

1. Break Down the Problem

Identify values for Y Y that are less than or equal to 2 2 . Exclude any probability mass for values greater than 2 2 .

2. Relevant Concepts

Joint probabilities typically are given in a probability distribution table. We need to sum the probabilities corresponding to the values of Y Y that satisfy Y2 Y \leq 2 .

3. Analysis and Detail

Assuming we have access to the specific joint probability table, we would locate and sum the probabilities P(Y=0) P(Y = 0) , P(Y=1) P(Y = 1) , and P(Y=2) P(Y = 2) : P(Y2)=P(Y=0)+P(Y=1)+P(Y=2) P(Y \leq 2) = P(Y = 0) + P(Y = 1) + P(Y = 2)

4. Verify and Summarize

After calculating the sum, verify that it indeed represents the cumulative probability for Y Y values up to 2 2 .

Final Answer

The value of P(Y2) P(Y \leq 2) based on your selections and the joint probability table is one of the given options: 316,116,332,364 \frac{3}{16}, \frac{1}{16}, \frac{3}{32}, \frac{3}{64} .

Without the actual table data, I cannot compute the exact total. Please provide the joint probability values for specific calculations.

This problem has been solved

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