orWatch a videoSolve the system of equations.y=–27x+8y=x2–27x–28Write the coordinates in exact form. Simplify all fractions and radicals.

To solve the system of equations, we need to set the two equations equal to each other because they both equal y.

So, we have:

-27x + 8 = x^2 - 27x - 28

We can simplify this by adding 27x to both sides and adding 28 to both sides:

0 = x^2 - 28 + 8

0 = x^2 - 20

To solve for x, we need to find the square root of 20. However, since this is a quadratic equation, we need to consider both the positive and negative roots. So, x can be either sqrt(20) or -sqrt(20).

Substitute x = sqrt(20) and x = -sqrt(20) into the original equations to find the corresponding y values.

For x = sqrt(20):

y = -27(sqrt(20)) + 8

y = sqrt(20)^2 - 27(sqrt(20)) - 28

Simplify to get the exact form of the coordinates.

Do the same for x = -sqrt(20).

This will give you the exact coordinates of the solutions to the system of equations.