What is the period of a simple pendulum that is 1.13-m long in each situation? In the physics lab
Question
What is the period of a simple pendulum that is 1.13-m long in each situation?
In the physics lab
Solution
The period of a simple pendulum can be calculated using the formula:
T = 2π √(L/g)
where: T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
In this case, the length L is given as 1.13 m. The acceleration due to gravity g is approximately 9.8 m/s² on the surface of the Earth.
Substituting these values into the formula gives:
T = 2π √(1.13/9.8)
Calculating the square root and the multiplication gives a period T of approximately 2.14 seconds.
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