the period of a simple pendulum is 1s on earth when brought to a planet where g is one-tenth that of the earth its period become

The period of a simple pendulum is given by the formula T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity.

On Earth, we know that T = 1s and g = 9.8 m/s². We can use these values to find the length of the pendulum:

1 = 2π√(L/9.8) Squaring both sides, we get: 1² = (2π)² * (L/9.8) 1 = 4π²L/9.8 Solving for L, we find that L = 9.8 / (4π²) ≈ 0.2485 m.

Now, if we bring the pendulum to a planet where g is one-tenth that of Earth, g = 0.98 m/s². We can substitute these values back into the formula to find the new period T':

T' = 2π√(L/g') = 2π√(0.2485/0.98) = 2π√(0.2536) ≈ 3.16s.

So, the period of the pendulum on the new planet would be approximately 3.16 seconds.