Which ion requires the greatest number of coulombs to reduce one mole of the ion to the element?Group of answer choicesSn2+Co3+Ni2+K+

The amount of coulombs required to reduce one mole of an ion to its elemental form is determined by Faraday's Law of Electrolysis, which states that the amount of a substance deposited on each electrode of an electrolytic cell is directly proportional to the quantity of electricity that passes through the cell.

The formula for Faraday's Law is:

Q = n * F * z

where:

• Q is the total charge in coulombs
• n is the number of moles of electrons transferred
• F is Faraday's constant (approximately 96485.34 coulombs per mole of electrons)
• z is the charge of the ion

In this case, we are looking for the ion that requires the greatest number of coulombs to be reduced to its elemental form. This would be the ion with the highest charge, as a higher charge means more electrons are needed for reduction, and therefore more coulombs.

Looking at the ions given:

• Sn2+ has a charge of +2
• Co3+ has a charge of +3
• Ni2+ has a charge of +2
• K+ has a charge of +1

Therefore, Co3+ would require the greatest number of coulombs to reduce one mole of the ion to the element, as it has the highest charge.