1 pointWhat is the output of the following code?i = 1while True: if i%2 == 0: break print(i) i += 211 21 2 3 4 5 6 ...1 3 5 7 9 11 ...
Question
Solution 1
The output of the given code will be "1".
Here's the step by step explanation:
- The variable
i
is initialized with the value 1. - The
while True:
statement starts an infinite loop. - The
if i%2 == 0:
statement checks ifi
is divisible by 2 (i.e., ifi
is an even number). Ifi
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