Calculate the amount of heat required toraise the temperature of 2 moles of waterby 3°C. The specific heat capacity of wateris given as 4.18 − −1 1JK g
Question
Calculate the amount of heat required to raise the temperature of 2 moles of water by 3°C.
The specific heat capacity of water is given as 4.18 J/(g·°C).
Solution
To calculate the amount of heat required to raise the temperature of 2 moles of water by 3°C, we can use the formula:
Q = m * c * ΔT
Where: Q is the amount of heat m is the mass of the substance (in this case, water) c is the specific heat capacity of water ΔT is the change in temperature
Given that we have 2 moles of water, we need to convert this to mass. The molar mass of water is approximately 18 g/mol, so 2 moles of water would be 36 grams.
Now, we can substitute the values into the formula:
Q = (36 g) * (4.18 J/g°C) * (3°C)
Calculating this, we get:
Q = 449.28 J
Therefore, the amount of heat required to raise the temperature of 2 moles of water by 3°C is 449.28 Joules.
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