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Calculate the amount of heat required toraise the temperature of 2 moles of waterby 3°C. The specific heat capacity of wateris given as 4.18 − −1 1JK g

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Solution

To calculate the amount of heat required to raise the temperature of 2 moles of water by 3°C, we can use the formula:

Q = m * c * ΔT

Where: Q is the amount of heat m is the mass of the substance (in this case, water) c is the specific heat capacity of water ΔT is the change in temperature

Given that we have 2 moles of water, we need to convert this to mass. The molar mass of water is approximately 18 g/mol, so 2 moles of water would be 36 grams.

Now, we can substitute the values into the formula:

Q = (36 g) * (4.18 J/g°C) * (3°C)

Calculating this, we get:

Q = 449.28 J

Therefore, the amount of heat required to raise the temperature of 2 moles of water by 3°C is 449.28 Joules.

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