State whether the statements are correct or incorrect with reasons.1. O(f(n)) + O(f(n)) = O (2f(n))2. If 3n + 5 = O(n2) , then 3n + 5 = o(n2)
Question
State whether the statements are correct or incorrect with reasons.
-
O(f(n)) + O(f(n)) = O(2f(n))
- Reason:
-
If 3n + 5 = O(n^2) , then 3n + 5 = o(n^2)
- Reason:
Solution
- O(f(n)) + O(f(n)) = O(2f(n)) - Correct
Explanation: In Big O notation, when we add two functions, the dominant term is the one that determines the overall complexity. Since both O(f(n)) and O(f(n)) have the same function f(n), adding them together will still result in the same dominant term. Therefore, O(f(n)) + O(f(n)) is equivalent to O(2f(n)).
- If 3n + 5 = O(n^2), then 3n + 5 = o(n^2) - Incorrect
Explanation: In Big O notation, the symbol "O" represents an upper bound, while the symbol "o" represents a strict upper bound. If 3n + 5 is O(n^2), it means that there exists a constant c and a value n0 such that for all n ≥ n0, 3n + 5 ≤ c * n^2. However, this does not imply that 3n + 5 is strictly less than c * n^2 for all n ≥ n0. Therefore, we cannot conclude that 3n + 5 is o(n^2).
Similar Questions
State whether the statements are correct or incorrect with reasons.1. O(f(n)) + O(f(n)) = O (2f(n))2. If 3n + 5 = O(n2) , then 3n + 5 = o(n2)
Which of the given options provides the increasing order of complexity of functions f1, f2, f3 and f4:f1(n) = 2^nf2(n) = n^(3/2)f3(n) = nLognf4(n) = n^(Logn)
Answer and explain (no explanation - no credit): i. Is 2^(n+64) = O(2^n)? Why? ii. Is 2^3n = O(2^2n)? Why?
(15 points) Prove that the following assertion is true for all values of n ≥ n0. Identify both n0 and c.2n + 5∈ O(n2)
1. Determine whether each of these functions is O(x).a) f (x) = 10 b) f (x) = 3x + 7 c) f (x) = x2 + x + 1 d) f (x) = 5 log x
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.