The chemical equation for the reaction of acetic acid with aluminum hydroxide to form water and

The chemical reaction of acetic acid (CH3COOH) with aluminum hydroxide (Al(OH)3) to form water (H2O) and aluminum acetate (Al(CH3COO)3) can be written as follows:

3CH3COOH + Al(OH)3 → Al(CH3COO)3 + 3H2O

Here's the step-by-step process:

1. Identify the reactants which are acetic acid and aluminum hydroxide.
2. Identify the products which are water and aluminum acetate.
3. Write the unbalanced chemical equation: CH3COOH + Al(OH)3 → Al(CH3COO)3 + H2O
4. Balance the equation by adjusting the coefficients. The balanced equation is: 3CH3COOH + Al(OH)3 → Al(CH3COO)3 + 3H2O

This equation tells us that three molecules of acetic acid react with one molecule of aluminum hydroxide to produce one molecule of aluminum acetate and three molecules of water.