T(n)=n+4n2+8+16n4+32+⋯+Θ(nlg4)=lg(n−1)∑i=0 2in+2lg(n−1)∑i=0 4i+Θ(n2)=2lgn−12−1n+2⋅4lgn−14−1+Θ(n2)=(2lgn−1)n+23(4lgn−1)+Θ(n2)=(n−1)n+23(n2−1)+Θ(n2)=Θ(n2)

Question

T(n)=n+4n2+8+16n4+32+⋯+Θ(nlg4)=lg(n−1)∑i=0 2in+2lg(n−1)∑i=0 4i+Θ(n2)=2lgn−12−1n+2⋅4lgn−14−1+Θ(n2)=(2lgn−1)n+23(4lgn−1)+Θ(n2)=(n−1)n+23(n2−1)+Θ(n2)=Θ(n2)
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T(n)=n+4n2+8+16n4+32+⋯+Θ(nlg4)=lg(n−1)∑i=0 2in+2lg(n−1)∑i=0 4i+Θ(n2)=2lgn−12−1n+2⋅4lgn−14−1+Θ(n2)=(2lgn−1)n+23(4lgn−1)+Θ(n2)=(n−1)n+23(n2−1)+Θ(n2)=Θ(n2)

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