What will be the output of the following Python code?1. def foo():2. try:3. print(1)4. finally:5. print(2)6. 7. foo()

Question

1.  def foo():
2.      try:
3.          print(1)
4.      finally:
5.          print(2)
6.  
7.  foo()

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The output of the given Python code will be:

1 2

Here's the step by step explanation:

The function foo() is defined. Inside this function, there is a try block and a finally block.
The try block contains a print statement that prints the number 1.
The finally block contains a print statement that prints the number 2. The finally block is always executed regardless of whether an exception occurred in the try block or not.
After defining the function, it is called with foo().
When foo() is called, it first executes the try block, which prints out 1.
Then it executes the finally block, which prints out 2.

So, the output of this code is 1 followed by 2.

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