Find the area of the region bounded by the graphs of the algebraic functions: 𝑓(𝑥)=𝑥2+6𝑥+9 and 𝑔(𝑥)=5(𝑥+3).
Question
Find the area of the region bounded by the graphs of the algebraic functions:
f(x) = x² + 6x + 9
g(x) = 5(x + 3)
Solution
To find the area between two curves, we need to integrate the absolute difference of the two functions over the interval where they intersect.
Step 1: Set the two functions equal to each other to find the points of intersection.
x^2 + 6x + 9 = 5(x + 3)
Solving this equation gives us x = -3. So, the two functions intersect at x = -3.
Step 2: Find the area between the curves.
The area A between the two curves from x = a to x = b is given by the formula:
A = ∫ from a to b |f(x) - g(x)| dx
In this case, f(x) = x^2 + 6x + 9 and g(x) = 5(x + 3), and the interval is from -3 to -3.
However, since the interval is just a single point, the area between the curves is 0.
So, the area of the region bounded by the graphs of the algebraic functions f(x) = x^2 + 6x + 9 and g(x) = 5(x + 3) is 0.
Similar Questions
Find the area of the region bounded by the graphs of the algebraic functions: 𝑓(𝑥)=𝑥2+6𝑥+9 and 𝑔(𝑥)=5(𝑥+3).
Find the area (in sq. units) of the region bounded by the graph | x – 7 | + | y – 9 | = 12
Find the area of the region between the x-axis and the curve(a) y = e−3x for x ≥ 0. (b) y = 8x2−4 for x ≥ 4
Find the exact area of the region bounded by the graphs with equations:y = x + 3 and y = 12 + x − x2
Find the signed area between the 𝑥-axis and the graph of 𝑦=𝑥2−4 over the interval [2,4]
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.